Today we had questions 1-16 from the detailed analysis we got monday checked. We then had notes on how to find the horizontal range of a projectile, when given the angle the object was projected, the speed the object is traveling, and the acceleration due to gravity. The equation was: Range=(speed squared *sin2theta)/accelaration due to gravity. For this equation, gravity is given a positive value, and the final vertical position is to be the same as the initial vertical position in order for the equation to work. The rest of the period was spent finishing the detailed analysis, which is due Wednseday. Overall it was a relatively peaceful day. It was clear that Mrs. Coatsaan didn't know what to make of this, and was so used to interruptions that she interrupted herself with a fairly unrelated, but also fairly awesome picture of stone henge about to be demolished by an angry bird.
Q.O.D.: What are the steps to determine if the ball in today's problem reaches its maximum height before or after it reaches the edge of the cliff? To figure out if the ball will reach its maximum height before or after it reaches the edge of the cliff, all you will have to find is the time it takes for the ball to reach its highest point(use 5.75m/s+-9.81m/s^2*T=0m/s to find the time .587 seconds) and the time it takes for the ball to reach the cliff (use 5.00m=9.96m/s*t to find .502 seconds). You don't really have to do any calculating for this problem. Whatever point that takes a shorter duration of time for the ball to reach will be closer to the origin, and the ball will reach that point first. Since it takes less time to reach the cliff, the ball will reach the cliff before it reaches its maximum height.
No comments:
Post a Comment